0=-180x^2+303x-126

Solution for 0=-180x^2+303x-126 equation:

0=-180x^2+303x-126

We move all terms to the left:

0-(-180x^2+303x-126)=0

We add all the numbers together, and all the variables

-(-180x^2+303x-126)=0

We get rid of parentheses

180x^2-303x+126=0

a = 180; b = -303; c = +126;
Δ = b2-4ac
Δ = -3032-4·180·126
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-303)-33}{2*180}=\frac{270}{360}
=3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-303)+33}{2*180}=\frac{336}{360}
=14/15
$